Question

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consider a collusion in one dimension that invoves two objects of masses 4.5 kg and 6.2 kg the larger mass is originally at rest, and the smaller mass has an initial velocity of 16 m/s [E]. the final velocity of the larger object is 10.0 m/s [E]. calculate the final velocity of the smaller object after the collision.​

Answer 1

Answer:

v₁ = 1.78 m/s

Explanation:

We can use the law of conservation of momentum here, as follows:

$m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2$

where,

m₁ = mass of first object = 4.5 kg

m₂ = mass of second object = 6.2 kg

u₁ = initial speed of first (smaller) mass = 16 m/s

u₂ = initial speed of second (larger) mass = 0 m/s

v₁ = final speed of first (smaller) mass = ?

v₂ =  final speed of second (larger) mass = 10 m/s

Therefore,

$(4.5\ kg)(16\ m/s)+(6.2\ kg)(0\ m/s)=(4.5\ kg)(v_1)+(6.2\ kg)(10\ m/s)\\70\ kgm/s - 62\ kgm/s = (4.5\ kg)v_1\\\\v_1 = \frac{8\ kgm/s}{4.5\ kg}$

v₁ = 1.78 m/s