Question

find the image of U'( -8 , 1) after a translation along < 2 , 0 > and a reflection in the x axis
U"( -6 , -1)
U"(6 , 1)
U"(6 , -1)
U"(-1 , 6)

Answer 1

Given:

The point is U'(-8,1).

It is translated along <2,0> and reflected across the x-axis.

To find:

The image of U'.

Solution:

The given point is U'(-8,1).

It is translated along <2,0> . So, the rule of translation is:

$(x,y)\to (x+2,y+0)$

$U'(-8,1)\to U_1(-8+2,1+0)$

$U'(-8,1)\to U_1(-6,1)$

Then, it is reflected across the x-axis. So, the rule of reflection is:

$(x,y)\to (x,-y)$

$U_1(-6,1)\to U''(-6,-1)$

The image of U'( -8 , 1) is U''(-6,-1).

Therefore, the correct option is A.