Question

Think about the decomposition reaction of ozone.

2 O3 ----> 3 O2

If 71.7 mol ozone are in this reaction, what is the theoretical yield of O2 (in gram)?

Answer 1

Answer:

3441.6 grams.

Explanation:

2 O₃ → 3 O₂

First we convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂), using the stoichiometric coefficients of the reation:

71.7 mol O₃ * $\frac{3molO_2}{2molO_3}$ = 107.55 mol O₂

Then we convert 107.55 moles of O₂ into grams, using the molar mass of O₂:

107.55 mol * 32 g/mol = 3441.6 g