Respuesta :
the balanced chemical equation was shown here :
2 K3PO4 (aq) + 3 NiBr2(aq) ------------>> Ni3(PO4)2 (s) + 6 KBr (aq)
The balanced chemical equation when aqueous potassium phosphate reacts with aqueous nickel(II) bromide to produce solid nickel(II) phosphate and aqueous potassium bromide is:
2 K₃PO₄(aq) + 3 NiBr₂(aq) ⇒ Ni₃(PO₄)₂ + 6 KBr(aq)
Let's consider the unbalanced chemical equation that occurs when aqueous potassium phosphate reacts with aqueous nickel(II) bromide to produce solid nickel(II) phosphate and aqueous potassium bromide.
K₃PO₄(aq) + NiBr₂(aq) ⇒ Ni₃(PO₄)₂ + KBr(aq)
We will balance it using the trial and error method.
- We will balance Ni atoms by multiplying NiBr₂ by 3.
- We will balance P atoms by multiplying K₃PO₄ by 2.
2 K₃PO₄(aq) + 3 NiBr₂(aq) ⇒ Ni₃(PO₄)₂ + KBr(aq)
We will get the balanced equation by multiplying KBr by 6.
2 K₃PO₄(aq) + 3 NiBr₂(aq) ⇒ Ni₃(PO₄)₂ + 6 KBr(aq)
The balanced chemical equation when aqueous potassium phosphate reacts with aqueous nickel(II) bromide to produce solid nickel(II) phosphate and aqueous potassium bromide is:
2 K₃PO₄(aq) + 3 NiBr₂(aq) ⇒ Ni₃(PO₄)₂ + 6 KBr(aq)
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