Question

A container has a volume of 5.85 L and a pressure of 4.25 atm. What will the volume be
If the containers pressure is changed to 2.75 atm?

Answer 1

Answer:

9.04 L

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we're finding the new volume

$V_2 = \frac{P_1V_1}{P_2}$

We have

$V_2 = \frac{4.25 \times 5.85}{2.75} = \frac{24.8625}{2.75} \\ = 9.0409...$

We have the final answer as

9.04 L

Hope this helps you