Answer:
133.56kPa
Explanation:
Applying Pressure Law,
P/T = P'/T'....................... Equation 1
Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.
From the question, we were asked to calculate P'
There, we make P' the subject of the equation
P' = PT'/T...................... Equation 2
Given: P = 100kPa, T = 25°C = (273+25) = 298K, T' = 125°C = (273+1250K = 398 K
Substitute these values into equation 2
P' = (100×398)/298
P' = 133.56kPa
Hence the pressure is 133.56kPa
