I'm stuck on two polynomial questions and any help would be greatly appreciated!


1. (4x-3y) is a factor of [tex]a^{2}x^{2} -b^{2}y^{2}[/tex] what is the value of [tex]a^{2} + b^{2}[/tex]?


2. [tex]x^{2} +19x+c[/tex] has a factor of (x+7) what is the value of c?

Respuesta :

Answer:

  • 1) 25
  • 2) 84

Step-by-step explanation:

#1

a²x² - b²y² = (ax + by)(ax - by)

Since (4x - 3y) is one of the factors, we have:

  • a = 4, b = ± 3

The value of a² + b² is:

  • 4² + (±3)² = 16 + 9 = 25

#2

x² + 19x + c, has a factor of (x + 7).

It means the equation:

  • x² + 19x + c = 0 has one root of x₁ = -7.

Sum of the roots:

  • x₂ + (- 7) = -19/1
  • x₂ = -19 + 7
  • x₂ = -12

Product of the roots:

  • x₂*(-7) = c
  • -12*(-7) = c
  • c = 84

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