An object of mass m is moving in a straight line with velocity v and is slowing down from a force F = -kv where k is a constant. At time t = 0, the velocity is [tex]v_{0}[/tex]. How can I derive an equation for the object's velocity as a function of t?

An object of mass m is moving in a straight line with velocity v and is slowing down from a force F kv where k is a constant At time t 0 the velocity is texv0te class=

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Answer:

The equation of the object's velocity in time is [tex]v(t) = v_{o}\cdot e^{-\frac{k\cdot t}{m} }[/tex].

Explanation:

By Newton's Laws of Motion, the equation of motion that represents the deceleration of the object is described by:

[tex]\Sigma F = - k\cdot v = m\cdot \frac{dv}{dt}[/tex] (1)

Where:

[tex]k[/tex] - Damping constant, in newton-second per meter.

[tex]m[/tex] - Mass, in kilograms.

[tex]v[/tex] - Velocity, in meters per second.

[tex]\frac{dv}{dt}[/tex] - Acceleration, in meters per square second.

Then, we modify (1) until the following ordinary differential equation with separable variables is found:

[tex]-\frac{k}{m} \int \, dt = \int {\frac{dv}{v} }[/tex] (2)

Then, we integrate the equation and find the following solution:

[tex]-\frac{k}{m}\cdot (t-0) = \ln \frac{v}{v_{o}}[/tex]

[tex]- \frac{k\cdot t}{m} = \ln \frac{v}{v_{o}}[/tex]

Finally, we clear the velocity in the solution of the differential equation is:

[tex]v(t) = v_{o}\cdot e^{-\frac{k\cdot t}{m} }[/tex]

The equation of the object's velocity in time is [tex]v(t) = v_{o}\cdot e^{-\frac{k\cdot t}{m} }[/tex].

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