Question

Figure A is enlarged to create figure B. The ratio of the areas of A and B is 16:49.

One side of B is 5ft long. How long would the corresponding side on figure B be. Leave your answer as a fraction. (No image was provided, only the question itself.)​

Answer 1

Answer: $\dfrac{20}{7}$

Step-by-step explanation:

Given

The ratio of the area of the similar triangles is equal to the square of the side of the corresponding sides

Suppose the corresponding side on figure A is $x$

On solving

$\Rightarrow \dfrac{16}{49}=[\dfrac{x}{5}]^2\\\\\Rightarrow \dfrac{x}{5}=\sqrt{\dfrac{16}{49}}\\\\\Rightarrow \dfrac{x}{5}=\dfrac{4}{7}\\\\\Rightarrow x=\dfrac{20}{7}$