Question

18.6 in

Which is the best approximation for the measure of angle

EGF?

32.8°

40.2

OOO

49.8°

57.2

Answer 1

Answer:

The answer is "$40.2^{\circ}$"

Step-by-step explanation:

Please find the graph file.

Let

$\angle EGF = x\\\\\sin x = \frac{12}{18.6}\\\\\sin x = 0.6452 \\\\x = \sin^{-1} (0.64516129) \\\\x = 40.1777695^{\circ} \approx 40.2^{\circ}$