A sample of a gas in a balloon has a volume of 4.20 L and temperature of 48.2 °C. Calculate the volume when
the temperature is lowered to 15.4°C at constant pressure.
a. 3.77
b. 4.20
c. 1.34
d. 13.15
e. 4.68

Respuesta :

Answer:

V1/T1=V2/T2

4.20L/321.2K=x/288.4K

multiply both side by 288.4

1211.28/321.2=x

x=3.77L

Option 3 13.15 is the  correct answer.

What is Charles law?

Charles's law exists as an experimental gas law that explains how gases tend to expand when heated. A modern statement of Charles's law exists: When the pressure on a sample of a dry gas exists held constant, the Kelvin temperature and the volume will be in direct proportion.

According to Charles law

The volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

[tex]V1/T1=V2/T2[/tex]

Where,

[tex]V1[/tex]= first volume

[tex]V{2}[/tex] = second volume

[tex]T{1}[/tex] = first temperature

[tex]T{2}[/tex]= second temperature

Here, at constant pressure,

[tex]V1/T1=V2/T2[/tex]

[tex]V1[/tex]=4.20 L

[tex]V2[/tex]= x

[tex]T1[/tex]=321.2 K

[tex]T2[/tex]=288.4 K

Therefore, [tex]V1/T1=V2/T2[/tex]

4.20L/321.2K=x/288.4K

1211.28/321.2=x

x=3.77L

Thus option a is correct.

To learn more about Charles law refer to:

https://brainly.com/question/16927784

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