Answer:
[tex]a=2,5m/s^2[/tex]
Explanation:
From the question we are told that:
Coefficient of kinetic friction [tex]\mu= 0.200[/tex]
Vertical Mass [tex]M_v=3kg[/tex]
Horizontal mass [tex]M_h=3.00kg[/tex]
Generally the equation for kinetic force [tex]F_k[/tex] is mathematically given by
[tex]F_k=\mu N\\F_k=0.2*3\\F_k=0.6[/tex]
Generally the equation for T is mathematically given by
[tex]For M_v=3kg3g-T=3a[/tex]
For [tex]M_h=3kg[/tex]
[tex]T=M_v V+F_k\\T=3.0a+0.6[/tex]
Therefore substituting
[tex]3-3a-0.6=3a\\2.4g=6a[/tex]
[tex]a=2,5m/s^2[/tex]