Using trigonometric identities, it is found that the value of the tangent of the angle is given by:
B. [tex]-\frac{\sqrt{15}}{7}[/tex]
What is the tangent of an angle?
The tangent of an angle is given by it's sine divided by it's cosine, that is:
[tex]\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}[/tex]
In this problem, we have that:
[tex]\cos{\theta} = -\frac{7}{8}[/tex]
The following identity is applied:
[tex]\sin^2{\theta} + \cos^2{\theta} = 1[/tex]
Then:
[tex]\sin^2{\theta} + \left(-\frac{7}{8}\right)^2 = 1[/tex]
[tex]\sin^2{\theta} + \frac{49}{64} = 1[/tex]
[tex]\sin^2{\theta} = \frac{15}{64}[/tex]
[tex]\sin{\theta} = \pm \frac{\sqrt{15}}{8}[/tex]
Since it is on the second quadrant, it is positive, hence:
[tex]\sin{\theta} = \frac{\sqrt{15}}{8}[/tex]
Applying the tangent equation:
[tex]\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}[/tex]
[tex]\tan{\theta} = \frac{\frac{\sqrt{15}}{8}}{-\frac{7}{8}}[/tex]
[tex]\tan{\theta} = -\frac{\sqrt{15}}{7}[/tex]
More can be learned about trigonometric identities at https://brainly.com/question/22591162