A 65kg person throw a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the snowball. Both people on the skate. the first person is initially moving forward with speed of 2.5m/s, and the second person is initially at rest. what are the volocities of the two people after the snowball is exchanged? disregard friction between the skates and the ice

Respuesta :

Well, st first we should find initial momentum for the first person represented in the task which definitely must be :
[tex](65+0.045)*2.5[/tex]
And then we find the final one :  [tex]65*x + 0.045*30[/tex]
Then equate them together : [tex]x=2.48 m/s[/tex] 
So we can get the velocity, which is [tex] is 2.48 m/s[/tex]
In that way, according to the main rules of conservation of momentum you can easily find the solution for the second person.
Regards!
ACCESS MORE
EDU ACCESS
Universidad de Mexico