Question

20.
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

A(n)=-6+(n-1)($\frac{1}{5}$)

A. –6, $-5\frac{2}{5}$, $-4\frac{1}{5}$

B. 0, $\frac{3}{5}$, 1$\frac{4}{5}$

C. –6, -5$\frac{1}{5}$, -4

D. 5, -5$\frac{1}{5}$, 1$\frac{4}{5}$

Answer 1

Answer:

A. –6, ,

Step-by-step explanation:

answer is D. -6, -5 2/5, -4 1/5

A(1)=-6+(1-1)(1/5) = -6 + 0 = -6

A(4)=-6+(4-1)(1/5) = -6 + 3/5 = - 5 2/5

A(10)=-6+(10-1)(1/5) = -6 + 9/5 = -4 1/5

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