Question

An altitude is drawn from the vertex of an isosceles triangle, forming a right angle and two congruent triangles. As a result, the altitude cuts the base into two equal segments. The length of the altitude is 26 inches, and the length of the base is 18 inches. Find the triangle's perimeter. Round to the nearest tenth of an inch.

Answer 1

Answer:

if it was 29inches it would be 78.7

Step-by-step explanation:

Answer 2

The given altitude and the base length of the triangle can be used for

finding the lengths of the other two sides.

The perimeter of the triangle is approximately 73.0 inches

Reasons:

The altitude is the perpendicular bisector of the base of the triangle

Length of the altitude = 26 inches

Length of the base of the triangle, b = 18 inches

Required:

The perimeter of the triangle

Solution:

The base length of the two congruent triangles formed are $\dfrac{18 \, cm}{2}$ = 9 cm

each.

Therefore;

The length of the hypotenuse side, L, is given by Pythagoras's theorem as

follows;

L² = 9² + 26² = 757

The hypotenuse side, L = The length of the equal sides of the isosceles triangle

Therefore, the perimeter of the triangle, P = b + 2·L

Which gives;

To the nearest tenth, the perimeter of the triangle, P = 18 + 2·√(757) ≈ 73.0

The perimeter of the triangle, P ≈ 73.0 inches

Learn more here:

https://brainly.com/question/19267912