Respuesta :

substitute x for 3 & y for -2

22 - 2(-2) = 26
3(2) + 2(-2) = 2

Answer:

3

Step-by-step explanation:

Given

[tex]\frac{x^2-xy}{x^2+2y}[/tex] ← substitute x = 3 and y = - 2

= [tex]\frac{3^2-3(-2)}{3^2+2(-2)}[/tex]

= [tex]\frac{9+6}{9-4}[/tex]

= [tex]\frac{15}{5}[/tex]

= 3

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