Answer:
Step-by-step explanation:
2) a) You have to find the area of semicircle.
r = d/2 = 12/2 = 6 mm
Area of semicircle = [tex]\frac{1}{2}\pi r^{2}[/tex]
[tex]= \frac{1}{2}*3.14*6*6\\\\= 3.14*3*6\\\\= 56.52 mm^{2}[/tex]
b) r = 10 cm
Area of quadrant = [tex]\frac{1}{4}\pi r^{2}[/tex]
[tex]= \frac{1}{4}*3.14*10*10\\\\=3.14*5*5\\\\= 78.5 cm^{2}[/tex]
3) d = 10 m
r = d/2 = 10/2 = 5 m
Area of circular garden = πr²
= 3.14 * 5 * 5
= 78.5 m²
Area of rectangular pool = 8 * 6 = 48 m²
Area of the garden covered in grass = area of the circular garden - area of pool
= 78.5 - 48
= 30.5 m²
4) a) r = 60 cm
Area of the top of the circular table = πr²
= 3.14 * 60 * 60
= 11304 cm²
diameter of base = 30 cm
r = 30/2 = 15 cm
Area of circular base = 3.14 * 15 * 15
= 706.5 cm²
