Respuesta :

Answer:

150°

Step-by-step explanation:

Consider OACB,

Here <CAO =<CBO= 90° ( As they are tangents)

<ACB= 30°

Now, <CAO +<CBO+<ACB+x= 360°

90°+90°+30°+x= 360°

x= 150°

Hope it helps

cairde

Answer:

150°

Step-by-step explanation:

Construct a line OC, and consider the resulting triangles ΔOAC.

<AOB=(1/2)x

<CAO=90

<ACO=30/2=15

Angles in a triangle add to 180, so

90+15+(x/2)=180

x/2=75

x=150°

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