Question

One of the legs of a right triangle measures 5 cm and its hypotenuse measures 9 cm.
Find the measure of the other leg. If necessary, round to the nearest tenth.

Can someone help please and thanks

Answer 1

answer is 7.5

${9}^{2} = {5}^{2} + {x}^{2} \\ 81 = 25 + {x}^{2} \\ - 25 \: \:- 25 \\ 56 = {x}^{2} \\ \sqrt{56} = \sqrt{x} \\ 7 .4833... \\ 7.5$