Question

3. Given the following equation:
2 K+ Cl2 --->2 KCI
How many grams of KCl are produced from 2.50 g of K and excess Cl2?

show work.

Answer 1

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

The balanced equation is

2 K+ Cl2 --->2 KCI

Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K

Mass of one atom/mole of potassium is 39.098 grams

Number of moles is 2.5 grams = $\frac{2.5}{39.098} = 0.064$

So, 2 moles of K produces 2 moles of KCL

0.064 moles of K will produces 0.064 moles of KCl

Mass of one molecule of KCl is 74.5513 g/mol

Mass of 0.064 moles of KCl is 4.767 grams

Answer 2

The mass of KCl produced is 4.77g

Stoichiometry

From the question, we are to determine the mass of KCl produced

From the given balanced chemical equation,

2K + Cl₂ → 2KCl

This means,

2 moles of potassium reacts with 1 mole of Chlorine to produce 2 moles of potassium chloride

First, we will determine the number of moles of potassium (K) present.

Using the formula,

$Number\ of \ moles = \frac{Mass }{Atomic\ mass}$

Atomic mass of K = 39.098 g/mol

Then,

Number of moles of K present = $\frac{2.50}{39.098}$

Number of moles of K present = 0.06394 mole

Now,

If 2 moles of K reacts to produce 2 moles of KCl

Then,

0.06394 moles of K reacts to produce 0.06394 moles of KCl

Thus, the number of moles of KCl produced is 0.06394.

Now, for the mass of KCl produced

From the formula,

Mass = Number of moles × Molar mass

Molar mass of KCl = 74.5513 g/mol

Then,

Mass of KCl produced = 0.06394 × 74.5513

Mass of KCl produced = 4.7668 g

Mass of KCl produced = 4.77 g

Hence, the mass of KCl produced is 4.77g

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