Answer:
The 96th term of the arithmetic sequence is -1234.
Step-by-step explanation:
first term (a)=1
second term (t2)=-12
common difference (d)= t2-a
d=-12-1
d=-13
96th term (t96)=?
We know that,
t96=a+(n-1)d
t96=1+(96-1)(-13)
t96=1+95(-13)
t96=1-1235
t96=-1234
