Answer: The final volume will be 2.89 L.
Explanation:
Given: [tex]T_{1} = 73^{o}C = (73 + 273) K = 346 K[/tex], [tex]V_{1} = 5L[/tex], [tex]T_{1} = 400 K[/tex]
[tex]P_{1}[/tex] = 101.3 kPa
Convert kPa to atm as follows.
[tex]1 kPa = 0.00986923\\101.3 kPa = 101.3 kPa \times \frac{0.00986923 atm}{1 kPa}\\= 0.99 atm\\= 1 atm[/tex]
[tex]P_{2}[/tex] = 1520 torr
Convert torr into atm as follows.
[tex]1 torr = 0.00131579 atm\\1520 torr = 1520 torr \times \frac{0.00131579 atm}{1 torr}\\= 2 atm[/tex]
Formula used to calculate final temperature is as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1 atm \times 5 L}{346 K} = \frac{2 atm \times V_{2}}{400 K}\\V_{2} = 2.89 L[/tex]
Thus, we can conclude that the final volume will be 2.89 L.
