Answer:
Step-by-step explanation:
Volume of a triangular pyramid = [tex]\frac{1}{3}(\text{Area of the triangular base})(\text{Height})[/tex]
1). Volume of the pyramid = [tex]\frac{1}{3}(72)(15)[/tex]
= 360 cm³
2). Volume of the pyramid = [tex]\frac{1}{3}(\text{Area of the triangular base})(\text{Height})[/tex]
Area of the triangular base = [tex]\frac{1}{2}(\text{Base})(\text{height})[/tex]
= [tex]\frac{1}{2}(8)(5)[/tex]
= 20 cm²
Therefore, volume of the pyramid = [tex]\frac{1}{3}(20)(12)[/tex]
= 80 cm³
5). Volume of the cone = [tex]\frac{1}{3}\pi r^{2}h[/tex]
Here, r = radius of the circular base
h = Height of the cone
Volume of the cone = [tex]\frac{1}{3}\pi (2)^2(4)[/tex]
= [tex]\frac{16\pi }{3}[/tex]
= 16.76 cm³
