Answer:
Area of the composite figure = 84 in²
Step-by-step explanation:
Area of the composite figure = Area of rectangle DEFG + Area of rectangle BCGH + Area of triangle ABH
Area of rectangle DEFG = DE × EF
= 5 × 10
= 50 in²
From ΔBHA,
AB = ED = 5 in [Given]
AH = FA - (GH + FG)
= 15 - (7 + 5)
= 15 - 12
= 3 in.
By applying Pythagoras theorem in ΔABH,
AB² = HB² + AH²
5² = HB² + 3²
25 - 9 = HB²
HB = √16
HB = 4 in
Area of rectangle BCGH = BC × HB
= 7 × 4
= 28 square in.
Area of triangle ABH = [tex]\frac{1}{2}(\text{Height})(\text{Base})[/tex]
= [tex]\frac{1}{2}(BH)(AH)[/tex]
= [tex]\frac{1}{2}(4)(3)[/tex]
= 6 in²
Therefore, area of the composite figure = 50 + 28 + 6
= 84 in²
