Answer: The number of molecules in a 45.6 gram sample of [tex]C_{2}H_{4}[/tex] are [tex]9.78 \times 10^{23}[/tex].
Explanation:
Given: Mass of [tex]C_{2}H_{4}[/tex] = 45.6 g
Molar mass of [tex]C_{2}H_{4}[/tex] is 28.05 g/mol.
Therefore, number of moles of [tex]C_{2}H_{4}[/tex] are calculated as follows.
[tex]No. of moles = \frac{mass}{molarmass}\\= \frac{45.6 g}{28.05 g/mol}\\= 1.62 mol[/tex]
According to the mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] molecules. Hence, number of molecules present in 1.62 mol are calculated as follows.
[tex]1.62 \times 6.022 \times 10^{23}\\= 9.78 \times 10^{23}[/tex]
Thus, we can conclude that the number of molecules in a 45.6 gram sample of [tex]C_{2}H_{4}[/tex] are [tex]9.78 \times 10^{23}[/tex].