Refer to the accompanying data set and use the 30 screw lengths to construct a frequency distribution. Begin with a lower class limit of 3.470 ​in., and use a class width of 0.010 in. The screws were labeled as having a length of 3 1/2 in

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Answer:

Answer:

A) Total frequency = 30

B) Yes, the distribution is consistent with the label because the frequencies are greatest when the lengths are closest to the labeled size of 1/2 inches which is 0.5 inches.

Step-by-step explanation:

Since the class limit width is 0.010 from the question, we arrive at;

Class Limits Frequency

Length(Inches)

0.470 - 0.479 3

0.480 - 0. 489 5

0.490 - 0.499 9

0.500 - 0.509 12

0.510 - 0.519 1

Following is the frequency distribution table:

How to build a frequency table?

The lower limit is given as 3.470 inches.

The upper limit is 3.500 inches.

And the width of each class is 0.010 inches.

Therefore, the intervals will be:

3.470-3.480

3.480-3.490

3.490-3.500

To know more about frequency tables problems refer:

https://brainly.com/question/16148316

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