Answer:
[tex]1.6m^3[/tex] sand is to be added to make sand percentage [tex]60\%[/tex]
Step-by-step explanation:
From the question we are told that:
Total soil [tex]N=3.2m^3[/tex]
Initial sand percentage [tex]S_1=40\%[/tex]
Final sand percentage[tex]s_2=60\%[/tex]
Generally the sand and other particles division is mathematically given by
[tex]40\% of 3,2=1.28[/tex]
and
[tex]60\% of 3.2=1.92[/tex]
Generally what will make 60\% of 3.2 40\% is mathematically given by
[tex]x=1.92*0.4\\x=4.8[/tex]
Generally the sand to be added is mathematically given by
[tex]4.8sand-3.2sand =1.6m^3[/tex]
Therefore
[tex]1.6m^3[/tex] sand is to be added to make sand percentage [tex]60\%[/tex]