charlesceeceeh488 charlesceeceeh488
  • 28-04-2021
  • Mathematics
contestada

In ΔNOP, n = 7.4 cm, o = 8.7 cm and ∠P=61°. Find the area of ΔNOP, to the nearest 10th of a square centimeter

Respuesta :

adefunkeadewole adefunkeadewole
  • 29-04-2021

Answer:

28.15 cm²

Step-by-step explanation:

In ΔNOP, n = 7.4 cm, o = 8.7 cm and ∠P=61°. Find the area of ΔNOP, to the nearest 10th of a square centimeter

For the above question, we are given 2 sides and an angle.

The formula to find the area of ΔNOP

1/2 × a × b × sin θ

From the above question:

θ = 61°

a = 7.4 cm

b = 8.7 cm

Hence,

1/2 × 7.4 × 8.7 × sin 61

= 28.154008373 cm²

Approximately to the nearest tenth = 28.15 cm²

Answer Link
loveblue0706
loveblue0706 loveblue0706
  • 17-04-2022

Answer:

28.2

Step-by-step explanation:

deltamath

Answer Link

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