Question

In the figure below,the segments JK and JL are tangent to the circle centered at O.Given that JL =13.2 and OJ=16.5,find OK.

Answer 1

Answer:

OK=9.9

Step-by-step explanation:

KJ and LJ both are on the circumference, are secants and coincides at the same outer point so they are equal.

JK=LJ so JK=13.2

Tangents are perpendicular to radius so the triangle in the circle is a right triangle.

Apply pythagorean theorem to find OK

${x}^{2} + 13.2 {}^{2} = 16.5 {}^{2}$

$x = 9.9$