Answer:
[tex](c)\ 9 - (3 * 2) \div 3 + 6[/tex]
Step-by-step explanation:
Given
(a) to (d)
Required
Which equals 13
[tex](a):\ 9 + 3 * (2 \div 3) + 6[/tex]
Solve the bracket
[tex]9 + 3 * (2 \div 3) + 6 =9 + 3 * (\frac{2}{3}) + 6[/tex]
Open the bracket
[tex]9 + 3 * (2 \div 3) + 6 =9 +2 + 6[/tex]
[tex]9 + 3 * (2 \div 3) + 6 == 17[/tex]
[tex](b):\ (9 + 3) * 2 \div 3 + 6[/tex]
Solve the bracket
[tex](9 + 3) * 2 \div 3 + 6 =(12) * 2 \div 3 + 6[/tex]
Open bracket
[tex](9 + 3) * 2 \div 3 + 6 =24 \div 3 + 6[/tex]
Divide
[tex](9 + 3) * 2 \div 3 + 6 =8 + 6[/tex]
[tex](9 + 3) * 2 \div 3 + 6 =14[/tex]
[tex](c)\ 9 - (3 * 2) \div 3 + 6[/tex]
Solve the bracket
[tex]9 - (3 * 2) \div 3 + 6 =9 - (6) \div 3 + 6[/tex]
Remove bracket
[tex]9 - (3 * 2) \div 3 + 6 =9 - 6 \div 3 + 6[/tex]
Divide
[tex]9 - (3 * 2) \div 3 + 6 =9 - 2 + 6[/tex]
[tex]9 - (3 * 2) \div 3 + 6 =13[/tex]
[tex](d)\ (9 + 3 * 2) \div 3 + 6[/tex]
Solve the bracket (the product, first)
[tex](9 + 3 * 2) \div 3 + 6=(9 + 6) \div 3 + 6[/tex]
[tex](9 + 3 * 2) \div 3 + 6=15 \div 3 + 6[/tex]
Divide
[tex](9 + 3 * 2) \div 3 + 6=5 + 6[/tex]
[tex](9 + 3 * 2) \div 3 + 6=11[/tex]
Only (c) equals 13
