Question

The length of a garden is 6 feet more than the width. The area is 40 square feet. write an algebraic equation to determine the length and width of the garden. What is the length, in feet, of the garden?​

Answer 1

Answer:

$(y + 6 = x) \times (x - 6 = y) = {40}^{2} feet$

Step-by-step explanation:

$(y + 6 = x) \times (x - 6 = y) = {40}^{2} feet \\ 6 \times 6 = 36 \\ 40 - 36 = 4 \\ (4 + 6 = 10) \times (10 - 6 = 4) \\ 10 \times 4 \\ = 40$