The triangular prism shown below is 6 \,\text{cm}6cm6, start text, c, m, end text wide and 4\,\text{cm}4cm4, start text, c, m, end text deep. The vertical height is 7\,\text{cm}7cm7, start text, c, m, end text. What is the length of the side edge, sss, of the triangular prism?

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Answer:

The answer is "7.62 cm ".

Step-by-step explanation:

Given:

[tex]Width = 6\ cm \\\\Depth = 4 \ cm\\\\Vertical \ height = 7 \ cm\\\\[/tex]

Dividing the prism's face into two halves:

As just a result, the vertical height becomes 7cm, as well as the width, becomes [tex]\frac{6\ cm}{2} = 3 \ cm[/tex]. If the 's' on both sides of the edge is equal:

[tex]s^2 = width^2 + height^2\\\\[/tex]

   [tex]= \sqrt{(width^2 + height^2)}\\\\[/tex]  

   [tex]= \sqrt{(3^2 + 7^2)}\\\\= \sqrt{9 + 49}\\\\= \sqrt{58}\\\\= 7.62 \ cm[/tex]

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