Answer:
At least 98 is needed in the 5th game
Step-by-step explanation:
The missing parameters are:
[tex]Game\ 1 = 95[/tex]
[tex]Game\ 2 = 91[/tex]
[tex]Game\ 3 = 77[/tex]
[tex]Game\ 4 =89[/tex]
[tex]Mean = 90[/tex] at least
Required
The score in game 5 to make you advance
Mean is calculated as:
[tex]Mean = \frac{\sum x}{n}[/tex]
So, we have:
[tex]Mean = \frac{95 + 91 + 77 + 89 + Game\ 5}{5}[/tex]
[tex]Mean = \frac{352 + Game\ 5}{5}[/tex]
The mean must be at least 90.
So, we have:
[tex]\frac{352 + Game\ 5}{5} \ge 90[/tex]
Multiply both sides by 5
[tex]5 * \frac{352 + Game\ 5}{5} \ge 90 * 5[/tex]
[tex]352 + Game\ 5 \ge 450[/tex]
Make Game 5 the subject
[tex]Game\ 5 \ge450 - 352[/tex]
[tex]Game\ 5 \ge 98[/tex]
At least 98 is needed in the 5th game