Respuesta :

Answer:

At least 98 is needed in the 5th game

Step-by-step explanation:

The missing parameters are:

[tex]Game\ 1 = 95[/tex]

[tex]Game\ 2 = 91[/tex]

[tex]Game\ 3 = 77[/tex]

[tex]Game\ 4 =89[/tex]

[tex]Mean = 90[/tex] at least

Required

The score in game 5 to make you advance

Mean is calculated as:

[tex]Mean = \frac{\sum x}{n}[/tex]

So, we have:

[tex]Mean = \frac{95 + 91 + 77 + 89 + Game\ 5}{5}[/tex]

[tex]Mean = \frac{352 + Game\ 5}{5}[/tex]

The mean must be at least 90.

So, we have:

[tex]\frac{352 + Game\ 5}{5} \ge 90[/tex]

Multiply both sides by 5

[tex]5 * \frac{352 + Game\ 5}{5} \ge 90 * 5[/tex]

[tex]352 + Game\ 5 \ge 450[/tex]

Make Game 5 the subject

[tex]Game\ 5 \ge450 - 352[/tex]

[tex]Game\ 5 \ge 98[/tex]

At least 98 is needed in the 5th game

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