Question

Calculate the value of Delta H for the reaction CaCO3 --> CO2 + CaO from the following enthalpy changes:
Ca + C + 3/2 O2 --> CaCO3 ΔH = -1206.9 kJ
Ca + ½ O2 --> CaO ΔH = -635.1 kJ
C + O2 -->CO2 ΔH= - 393.5 kJ

Answer 1

Explanation:

crescents discuss wentz eg

Answer 2

Answer:

2,2,1,2

2 Ca + 2 CO2 + 1 O2 → 2 CaCO3

Explanation:

Got it right on Oddesyware!!!!