Question

I have a 3 yellow m&m's, 5 blue m&m's, and 4 red m&m's. What is the probability if I choose a red and do not not put it back and then choose a yellow?

Answer 1

Answer:

8.3% probability

Step-by-step explanation:

(3) YELLOW  ⇒   $\frac{3}{12}$   ⇒  25%

(5) BLUE       ⇒   $\frac{5}{12}$   ⇒  41.6%

(4) RED         ⇒   $\frac{4}{12}$   ⇒  33.3%

║(12) IN TOTAL

$\frac{4}{12}$ ⋅ $\frac{3}{12}$ = $\frac{1}{12}$

$\frac{1}{12}$ = 8.3%

PROBABILITY OF (1) RED, AND (1) YELLOW  ⇒ 8.3% probability