two passenger train traveling in opposite directions meet and pass each other. Each train is 1/18 miles long and is traveling at 40 miles per hr. How many seconds after the front parts of the trains will meet their rear parts pass each other.

Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...

time = distance/speed

time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s

That is, the rear part of each train will be at point A 5 seconds after the front part.

The rear parts will pass each other 5 seconds after the front parts meet.

two passenger train traveling in opposite directions meet and pass each other. Each train is 1/18 miles long and is traveling at 40 miles per hr. How many seconds after the front parts of the trains will meet their rear parts pass each other.​

Respuesta :

Otras preguntas

two passenger train traveling in opposite directions meet and pass each other. Each train is 1/18 miles long and is traveling at 40 miles per hr. How many seconds after the front parts of the trains will meet their rear parts pass each other.