Question

Solve the quadratic a ( ^ means to the power of)


1) K^2 - 12k = 0

2) X^2 -19x = 0

Answer 1

k^2-12k=0
k(k-12)=0
set to zero
k=0
k-12=0
k=12

k=0 or 12



2.
x^2-19x=0
x(x-19)=0
set to zer o
x=0
x-19=0
x=19

x=0 or 19




1.  x=0 or 12
2. x=0 or 19