Step-by-step explanation:
For 18:
[tex] {10}^{2} + {y}^{2} = {26}^{2} \\ 100 + {y}^{2} = 676 \\ {y}^{2} = 676 - 100 \\ {y}^{2} = 576 \\ y = \sqrt{576} \\ y = 24 \: in[/tex]
For 19
[tex] {10}^{2} + {( \frac{15}{2}) }^{2} = {c}^{2} \\ 100 + \frac{225}{4} = {c}^{2} \\ \frac{625}{4} = {c}^{2} \\ c = \sqrt{ \frac{625}{4} } \\ c = \frac{25}{2} \\ c = 12.5 \: m[/tex]
