Answer:
n = 4
Step-by-step explanation:
Given
[tex]\sqrt{64}[/tex] × [tex]\sqrt[3]{8}[/tex]
= 8 × 2
= 2³ × [tex]2^{1}[/tex]
= [tex]2^{(3+1)}[/tex]
= [tex]2^{4}[/tex] → with n = 4
