Question

Which rule describes the composition of transformations that maps triangle BCD to triangle B""C""D""?

Answer 1

Answer:

(d)

Step-by-step explanation:

Given

See attachment for $\triangle BCD$ and $\triangle B"C"D"$

Required

The transformations

Using B and B"" as points of reference, we have:

$B = (1,4)$

$B"" = (5,-1)$

The transformation is as follows:

First, reflect across y axis.

The rule is:

$(x,y) \to (-x,y)$

So, we have:

$B(1,4) \to B'(-1,4)$

Next, translate 6 units right.

The rule is:

$(x,y) \to (x + 6,y)$

So, we have:

$B' (-1,4) \to B"(-1 + 6,4)$

$B' (-1,4) \to B"(5,4)$

Lastly, translate 5 units down

The rule is:

$(x,y) \to (x,y-5)$

So, we have:

$B"(5,4) \to (5,4-5)$

$B"(5,4) \to (5,-1)$

Hence; (d) is correct