Answer:
95% confidence interval for the mean
(6.61251, 7.38749)
Step-by-step explanation:
Step:-1
Given that a random sample 'n' = 60
Given that mean of the sample x⁻ = 7.0
Given that the standard deviation of the sample (S) = 1.5
Level of significance = 0.05
Degrees of freedom = n-1 = 60-1 = 59
t₍₀.₀₅ , ₙ₋₁₎ = 2.0010
Step(ii):-
95% confidence interval for the mean is determined by
[tex](x^{-} - t_{0.05,n-1} \frac{S.D}{\sqrt{n} } , x^{-} + t_{0.05 , n-1} \frac{S.D}{\sqrt{n} } )[/tex]
[tex]( 7.0 - 2.0010 \frac{1.5}{\sqrt{60} } , 7.0 + 2.0010 \frac{1.5}{\sqrt{60} } )[/tex]
(7.0 - 0.38749 , 7.0 + 0.38749)
(6.61251 , 7.38749)
Final answer:-
95% confidence interval for the mean
(6.61251 , 7.38749)
