Answer:
3x-y+6=0.......(1)
y+2x=5........(2)
[m1]slope of line 1=- coefficient of x/coefficient of y=3
[m2]=slope of line 2=- coefficient of x/coefficient of y=-2
we have
tan ø=[tex] \frac{m1 - m2}{1 + m1m2} [/tex]
tan ø=[tex] \frac{3+2}{1 + 3×-2} [/tex]
tan ø=[tex] \frac{5}{-5} [/tex]
tan ø=-1
ø=135°
obtuse angle between the pair of line is 135°