Respuesta :

msm555

Answer:

3x-y+6=0.......(1)

y+2x=5........(2)

[m1]slope of line 1=- coefficient of x/coefficient of y=3

[m2]=slope of line 2=- coefficient of x/coefficient of y=-2

we have

tan ø=[tex] \frac{m1 - m2}{1 + m1m2} [/tex]

tan ø=[tex] \frac{3+2}{1 + 3×-2} [/tex]

tan ø=[tex] \frac{5}{-5} [/tex]

tan ø=-1

ø=135°

obtuse angle between the pair of line is 135°

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