I am stuck on this one.

Answer: [tex]-\frac{\sqrt{3} }{3}[/tex]
Step-by-step explanation:
Tan is [tex]\frac{sin}{cos} \\\\[/tex]
sin is the y coordinate
Cos is the x-coordinate
[tex]\ \frac{11\pi }{6} = (\frac{\sqrt{3} }{2} ,-\frac{1}{2})\\[/tex]
[tex]tan=\frac{\frac{1}{2} }{\frac{\sqrt{3} }{2} }[/tex]
[tex]-\frac{1}{2} *\frac{2}{\sqrt{3} } =- \frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =-\frac{\sqrt{3} }{3}[/tex]