Write the equation of the circle graphed below

Answer:
(x-4)² + (y-3)² =29
Step-by-step explanation:
The equation of a circle is
(x-h)² + (y-k)² = r², where (h, k) is the center of the circle and r is the radius.
In this circle, the center is at (4, 3)
(x-4)² + (y-3)² = r²
and we have point (-1 ; 1)
r²=(-1-4)² + (1-3)² = 25+4=29
(x-4)² + (y-3)² =29
Answer:
(x - 4)² + (y - 3)² = 29
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k ) = (4, 3 )
The radius r is the distance from the centre to a point on the circle.
Calculate r using the distance formula
r = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (- 1, 1) and (x₂, y₂ ) = (4, 3)
r = [tex]\sqrt{(4+1)^2+(3-1)^2}[/tex]
= [tex]\sqrt{5^2+2^2}[/tex]
= [tex]\sqrt{25+4 }[/tex] = [tex]\sqrt{29}[/tex]
Then
(x - 4)² + (y - 3)² = ([tex]\sqrt{29}[/tex] )² , that is
(x - 4)² + (y - 3)² = 29 ← equation of circle