Answer: [tex]30^{\circ}[/tex]
Step-by-step explanation:
Given
[tex]\sin 60=\dfrac{\sqrt{3}}{2}[/tex]
For
[tex]\cos \theta =\dfrac{\sqrt{3}}{2}[/tex]
It indicates [tex]\theta[/tex] lies in I st quadrant. The value of cosine [tex]30^{\circ}[/tex] is equal to [tex]\dfrac{\sqrt{3}}{2}[/tex]
Therefore, [tex]\theta[/tex] must be [tex]30^{\circ}[/tex]
