A bowl has 2 gold marbles, 3 blue marbles and 5 white marbles. A marble is randomly selected and then placed back in the bowl. You do this 5 times. What is the probability of choosing 1 gold marble, 1 blue marble and 3 white marbles?

Respuesta :

Answer:

2/10 or 1/5 gold, 3/10 blue and 5/10 or 2/5 white

Step-by-step explanation:

2+3+5=10

since you do this 5 times and get 5 marbles it can be:

2/10 or 1/5 gold, 3/10 blue and 5/10 or 2/5 white

The probability of choosing 1 gold marble, 1 blue marble and 3 white marbles is 2/5

Probability is the likelihood or chance that an event will occur.

If there are 2 gold marbles, 3 blue marbles and 5 white marble in the bowl, the total number of marbles will be 10 marbles.

Pr(1 gold marble) = 2/10 = 1/5

Pr(1 blue marble) = 3/10

Pr(3 white marble) = [tex]\frac{3}{5C_3} = \frac{3}{10}[/tex]

Add all the probability;

Pr(hoosing 1 gold marble, 1 blue marble and 3 white marbles) = 1/5 +3/10 + 3/10 = 8/10 = 2/5

Hence the probability of choosing 1 gold marble, 1 blue marble and 3 white marbles is 2/5

Learn more here: https://brainly.com/question/13604758

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