Question

⦁ An electron is moving through a 10 T magnetic field at a speed of 3.5 x107m/s perpendicular to the direction of the field. What is the force that applied on the charge?

Answer 1

Answer:

    F = 5.6 10⁻¹¹ N

Explanation:

The magnetic force is given by

         F = q v x B

The bold  indicate vectors, the scalar form of this expression is

         F = q v B sin θ

in this case they indicate that the speed and the magnetic field are perpendicular, so the angle is 90º and the sin 90 = 1

         F = q v B

the magnitude of the force is

         F = 1.6 10⁻¹⁹  3.5 10⁷ 10

         F = 5.6 10⁻¹¹ N