Given:
The equation of the circle is:
[tex]x^2+y^2=16[/tex]
To find:
The radius of the circle.
Solution:
The standard form of a circle is:
[tex](x-h)^2+(y-k)^2=r^2[/tex] ...(i)
Where, (h,k) is the center and r is the radius.
We have,
[tex]x^2+y^2=16[/tex]
In can be written as:
[tex]x^2+y^2=4^2[/tex] ...(ii)
On comparing (i) and (ii), we get
[tex]h=0[/tex]
[tex]k=0[/tex]
[tex]r=4[/tex]
Here, the center of the circle is the origin and the radius is equal to 4 units.
Therefore, the radius of the given circle is 4 units.