Question

solve the logarithmic equation rounding to the nearest ten-thousandth
3 log 2x = 4

Answer 1

First, divide both sides by 3 to get log2x = 4/3.

Since you know a regular log has base 10, another way to write log2x = 4/3 is 10^(4/3) = 2x.

Then, divide both sides by 2.

x = 10.7722

Answer 2

The required value logarithmic equation x is 10.772.

Given that,

logarithmic equation 3 log 2x = 4.

We have to determine,

The value of x of logarithmic equation.

According to the question,

To solve the logarithmic equation follow the steps given below.

Logarithmic equation; 3log 2x = 4

• First, divide both sides by 3 to get,

$log2x = \dfrac{4}{3}$

• A regular log has base 10, another way to write,

$log2x = \dfrac{4}{3}\\\\Taking \ log \ base \ 10 ,\\\\2x = 10^{\frac{4}{3}}\\\\2x = 10^{1.2}$

Then,

Divide both sides by 2.

$x = 10.772$

Hence, The required value logarithmic equation x is 10.772.

To know more about Logarithm click the link given below.

https://brainly.com/question/24070713